See what happens when you pass a double as argument when constructing BigDecimal objects in Java.
import java.math.BigDecimal; public class DoubleAsBigDecimalConstructorArgument { public static void main(String[] args) { // Prints 1.229999999999999982236431605997495353221893310546875 System.out.println(new BigDecimal(1.23)); // Prints 1.23 System.out.println(new BigDecimal("1.23")); // Prints 1.23 System.out.println(BigDecimal.valueOf(1.23)); } }
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